Population vs sample proportion: If a random sample of 300 a

In a certain population, 40 percent of the adults go to church regularly. If a random sample of 300 adults is selected from this population, what is the probability that the sample proportion will exceed 0.45?

Use the normal approx. to the binomial dist.

45% of 300 is 135, 40% of 300 is 120=np

\(\displaystyle \sqrt{(300)(\frac{2}{5})(\frac{3}{5})}=6\sqrt{2}={\sigma}\)

Don't forget the continuity correction.