emdorsheimer
New member
- Joined
- Oct 6, 2006
- Messages
- 17
A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft^2. What must be the width of the walkway to the nearest thousandth?
Let the width of the walkway be denoted by "w". Then the outer dimensions are given by:
(40 + 2w)*(30 + 2w)
Then the area equation is:
1200 + 140w + 4w^2 = 1800
4w^2 + 140w - 600 = 0
w^2 + 35w - 150 = 0
w = [-35+/-sqrt(35^2 + 600)]/2w = -35 + 24.49/2w = -5.25
My final answer doesn't match any. Do you know where I went wrong?
______________________________
Edited by stapel -- Reason for edit: formatting
Let the width of the walkway be denoted by "w". Then the outer dimensions are given by:
(40 + 2w)*(30 + 2w)
Then the area equation is:
1200 + 140w + 4w^2 = 1800
4w^2 + 140w - 600 = 0
w^2 + 35w - 150 = 0
w = [-35+/-sqrt(35^2 + 600)]/2w = -35 + 24.49/2w = -5.25
My final answer doesn't match any. Do you know where I went wrong?
______________________________
Edited by stapel -- Reason for edit: formatting