Help with solving (x+5/x^2-x) - (3/x) = 1/x-1

How can I solve this problem? I can't figure it out.

(x+5/x^2-x) - (3/x) = 1/x-1

Any help is appreciated.

I assume the equation is:
(x+5)/(x^2-x) -3/x = 1/(x-1) factor a x from first denominator
(x+5) /[x(x-1)] -3/x = 1/(x-1) we shall clear the denominators
multiply both sides of equal sign by x-1
(x+5)/x -3(x-1)/x =1 multiply both sides by x
(x+5) -3(x-1) =x clear brackets
x+5-3x+3=x combine likes on each side of the = sign
8-2x=x add 2x to each side
8=3x divide each side by 3
8/3=x answer

Arthur