haleofwi said:
Does this mean the following?
. . . . .\(\displaystyle \L \frac{2x}{3}\, -\,14\, =\, 4\)
Or this?
. . . . .\(\displaystyle \L \frac{2x}{3\, -\, 14}\, =\, 4\)
If the former, then you cannot combine the 3 and the 14 into the denominator, since the 14 isn't in there anyway.
haleofwi said:
Since the "11" is in the denominator, how could adding an 11 possibly "cancel" this off?
. . . . .\(\displaystyle \L \frac{2x}{-11}\, + \, 11\)
And even if it did somehow cancel the denominator, you would end up with a zero in the denominator, which isn't allowed.
Have you not studied fractions previously...?
Eliz.