Another one, this ones in variables and fractions

Okay, here's the problem,

(5/2)x + (1/4) +(3/4)x = (1/8)

The fractions are in parenthesis so I don't confuse anyone. x_X

I really dislike fractions. I'm wondering if I start by taking the 1/8 divided by 3/4 or what...Can someone show me how i'm supposed to work this problem?

Subtract 1/4 from both sides:


\(\displaystyle \L\\\frac{5}{2}x+\frac{3}{4}x=\frac{-1}{8}\)

Now, you have to make the denominators the same so you can add.

Multiply num and den of 5/2 by 2/2:

\(\displaystyle \L\\\frac{2}{2}\cdot\frac{5}{2}x+\frac{3}{4}x=\frac{-1}{8}\)

\(\displaystyle \L\\\frac{10}{4}x+\frac{3}{4}x=\frac{-1}{8}\)

Finish up?. That's not so hard, is it?.

Mizuki said:

(5/2)x + (1/4) +(3/4)x = (1/8)

Click to expand...

Remember that the likes of (5/2)x is same as 5x / 2
(that's 5 times x, then divide by 2)

So your equation can be rewritten:
5x/2 + 3x/4 = 1/8 - 1/4

Now you can clearly see ALL the denominators, and that 8 is the lcm;
so multiply each by 8:
20x + 6x = 1 - 2
26x = -1
x = -1/26 : kapish kapush?