Quadratic equations: checking solutions w/ discriminant

KimmyDean

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Nov 11, 2006
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I am not sure how to get started!

Calculate the discriminant and state how many real solutions each equation has:

4x<sup>2</sup> - 6x + 4 = 0

To find the discriminant, you use b<sup>2</sup> - 4ac:

(-6)<sup>2</sup> - 4(4)(4) = -28

Does that mean there is no real solutions, since it's negative?

Thank you :)

Edited because I was working on it all wrong!
 
yes
sqrt[b^2-4ac] if the discriminant is real and non 0 , there are two real roots
If the discriminant is negative then the square root is a "imaginary" number, and there are no real roots.
Arthur
 
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