Jane has a solution that is 65% slfuric acid and a solution that is 30% sulfric acid. How much of each should she mix to obtain 200ml of a 55% sulfuric acid solution?
Steps I have taken so far:
x+y=200
0.35x+.65y=200(.55)
x=200-y
plugged 200-y for x
0.35(200-y)+.65y=110
70-0.35y+.65y=110
-70+70-0.35y+.65y=110
0.3y=40
___ __
0.3 0.3
Lost from here... Are my steps taken so far correct? :shock:
Thank you
Steps I have taken so far:
x+y=200
0.35x+.65y=200(.55)
x=200-y
plugged 200-y for x
0.35(200-y)+.65y=110
70-0.35y+.65y=110
-70+70-0.35y+.65y=110
0.3y=40
___ __
0.3 0.3
Lost from here... Are my steps taken so far correct? :shock:
Thank you