need help with square root of the fraction 2/5x

K

Kaelee

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Dec 3, 2006

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1

• Dec 3, 2006

• #1

The problem is:

. . .square root of the fraction 2/5x

According to the book, the answer is square root of 50x over 5x. How did they get that?

 

M

mts

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Dec 1, 2006

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11

• Dec 3, 2006

• #2

Don't know.

Rationalise the denominator

sqrt(2)/sqrt(5x)

Multiply top and bottom by sqrt(5x)

(sqrt(5x)(sqrt(2))/(sqrt(5x)(sqrt(5x))

sqrt(10x)/(5x)

 

stapel

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Feb 4, 2004

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• Dec 3, 2006

• #3

Kaelee said:

square root of the fraction 2/5x

Click to expand...

Do you mean any of the following?

. . . . .sqrt[2] / (5x)

. . . . .sqrt[2/5] x

. . . . .sqrt[2/(5x)]

Thank you.

Eliz.