two solutions to 'number of arrangements of letters' Q

In how many ways can the letters of the word 'SETS' be arranged?

I have made two solutions:

Solution 1:
Number of possible ways = 4!=24
formula : from n things r things are picked up
when r=n

Solution 2:
Number of possible ways = 4!/2!=12

formula: from n things , permutation of p things alike , q things alike = n!/p! q! etc

Which (if either) would be correct? And why?

Thank you!

One of your answers is correct :wink:

How many DIFFERENT 4digit numbers can you make with digits 1,1,2,3 ?

Denis said:

One of your answers is correct :wink:

How many DIFFERENT 4digit numbers can you make with digits 1,1,2,3 ?

Click to expand...

but in my question , there was no "DIFFERENT" keyword as you have shown .

I am bit confused about which formula to use .

defeated_soldier said:

Which (if either) would be correct? And why?

Click to expand...

yes both formulas are correct but not properily applied. first one is correct (4!=24) because there are not two words alike. if there is a word "BBlikess" then it comes 8! / (2!*2!)