[MOVED] Find gen. soln to dy/dx = (2x^3 + 6)/y

icyhot2590

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Mar 18, 2007
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find the general solution of the differential solution

dy/dx = (2x^3 + 6)/y

dy/dx= [2x^3+6] / y
y [dy/dx]= [2x^3+6]
y dy =[2x^3+6] dx
y^2 /2 = 2x^4/4 +6x
y^2=x^4 +12x
y^2=x[x^3+12]

i got this far but i still need to find the general solution.... is it y^2 - x^4 +12x =c
 
icyhot2590 said:
i got this far but i still need to find the general solution.... is it y^2 - x^4 +12x =c
"You" got that far...? Or the tutor gave you that much in one of your other threads...?

:?

Eliz.
 
The general solution:

\(\displaystyle y^2 = x^4 + 12x + A\)

is best left in implicit form and not as "y = \(\displaystyle sqrt{x^4 + 12x + A}\)."
 
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