Determine the probability of not rolling a perfect square..
- Thread starter lisa.
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Re: Determine the probability of not rolling a perfect squar
Hello, lisa!
You found the probability of not rolling a "double".
The only squares that can be rolled are: \(\displaystyle 4\) and \(\displaystyle 9\).
Of the 36 outcomes,
. . "4" can be rolled in 3 ways: (1,3), (2,2), (3,1)
. . "9" can be rolled in 4 ways: (3,6), (4,5), (5,4), (6,3)
There are \(\displaystyle 7\) ways to roll a square.
. . Hence, there are: \(\displaystyle \,36\,-\,7\:=\:29\) ways to not roll a square.
Therefore: \(\displaystyle \,P(\text{not square}) \:=\:\L\frac{29}{36}\)
Hello, lisa!
You found the probability of not rolling a "double".
The only squares that can be rolled are: \(\displaystyle 4\) and \(\displaystyle 9\).
Of the 36 outcomes,
. . "4" can be rolled in 3 ways: (1,3), (2,2), (3,1)
. . "9" can be rolled in 4 ways: (3,6), (4,5), (5,4), (6,3)
There are \(\displaystyle 7\) ways to roll a square.
. . Hence, there are: \(\displaystyle \,36\,-\,7\:=\:29\) ways to not roll a square.
Therefore: \(\displaystyle \,P(\text{not square}) \:=\:\L\frac{29}{36}\)
