Trying to solve for the line parallel to the line

Dejenise28

New member
Joined
Apr 15, 2007
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Hello I am trying to solve this problem.
Find the equation for the line parallel to th eline -3x-6y=-2 having the same y-intercept as 3x-4y=-6.

Here is what I have done so far

-3x-6y=-2
+3x to both sides
-6y=3x-2 divide whole equation by -6
y=-1/2x=1/3

Second part
3x-4y=-6
-3x to both sides
-4y=-3x-6 divide whole equation by -4
y=3/4x+3/2

What do I do next?

Thank you for your time
 
you figured out the slope for the first line ... m = -1/2

you also have the y-intercept of the 2nd line ... b = 3/2

so, the equation of the line parallel to the first line (they will have the same slope) with y-intercept equal to that of the 2nd line ...

y = (-1/2)x + (3/2)

2y = -x + 3

x + 2y = 3
 
Find the equation for the line parallel to th eline -3x-6y=-2 having the same y-intercept as 3x-4y=-6.

Here is what I have done so far

-3x-6y=-2
+3x to both sides
-6y=3x-2 divide whole equation by -6
y=-1/2x=1/3

Second part
3x-4y=-6
-3x to both sides
-4y=-3x-6 divide whole equation by -4
y=3/4x+3/2

What do I do next?
If parallel to the first line, it starts out as y = -x/2 or y = -(1/2)x as you derived.

If the y intercept is to be the same as the second line, the desired line has the equation y = -x/2 + 3/2.
 
P.S. to Dejenise28: Welcome to FreeMathHelp! :D

Eliz.
 
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