one more: g(x)=x2-9 & h(x)=radical 3x+12

g(x)=x2-9 & h(x)=radical 3x+12

what is the function or how do i find it

Re: one more

\(\displaystyle \L\\g(x)=x^{2}-9 \;\ & \;\ h(x)=\sqrt{3x+12}\)

what is the function or how do i find it

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We don't know if you don't. What are you expected to do?. Composition function perhaps?.

Maybe g(h(x))?. Something like that?.

If it is a composition, i.e. g(h(x)), then insert h(x) into g(x) like so:

\(\displaystyle \L\\(\sqrt{3x+12})^{2}-9=3x+12-9=3(x+1)\)

See how that works?. I subed h(x) in for x in g(x).