graphing systems of inequalities

dwhit

New member
Joined
Apr 19, 2007
Messages
1
use substitution to solve each system of equations. If the system dose not have exactly one solution, state weather it has no solution or infinitely many solutions
2m+n=1
m-n=8


x=3-2y
2x+4y=6


use elimination to solve each system of equations
x+2y=6
x-3y=4


3x-y=11
x+y=5

3x+1= -7y
6x+7y=0


x - 5y=0
2x - 3y=7


2x+3y=8
x - y=2

I dont understand how to do these problems can you help me out please I just dont get it
 
Hi. We cannot effectively provide lessons in this environment. We can help supplement the work you have done, and offer advice on mistakes you may have made.

Your best bet would be to look at these tutorials

Solving by graphing: http://www.purplemath.com/modules/syslneq.htm
Solving with substitution: http://www.purplemath.com/modules/systlin4.htm
Solving with elimination: http://www.purplemath.com/modules/systlin5.htm

And if I may nitpick your title... these equations are equal (balanced), therefor they aren't really inequalities, right? an inequalitie would be denoted with a greator than or less than symbol. (>,<) Second, you asked for help solving using the algebraic methods...is that really graphing?

I will help you on the first one. (using substitution)

2m+n=1
m-n=8

You want to solve for both variables, m and n.
It would be easier, to use the bottom equation in your substitution. With this, you could set

So, m = 8+n

Plug (8+n) into m in the first or second equation: I will use the first.

2(8+n)+n = 1

Solve for n

n = -5

When you have the value for n, plug the value for n into either equation, and solve for the value of m.
This could go the same if you solved for the value of m, first...in that case you would then solve for the value of n

Fun, huh?

Best of luck.
 
Top