Re: Square Roots
Hello again alwaysalillost! See my previous thread w/you here for a more detailed explanation:
Link
1. \(\displaystyle \L \;\sqrt{50x^2}\)
Simplify the sqrt 50 getting something squared until you can't any more. Pull out that pair of something. x^2 is x * x so pull out a pair of x.
2. \(\displaystyle \L \;3\sqrt{2}\,+\,5\sqrt{2}\)
See my previous thread.
3. \(\displaystyle \L \;sqrt{\frac{m^2}{n^3}\)
This is can be rewritten as \(\displaystyle \;\frac{\sqrt{m^2}}{\sqrt{n^3}}\)
So pull out a pair of m's and n's. You'll be left with \(\displaystyle \frac{m}{n\sqrt{n}}\)
4.\(\displaystyle \L \;\sqrt{2}\,+\,sqrt{\frac{2}{49}\)
Let's simplify the bottom of \(\displaystyle \frac{\sqrt{2}}{\sqrt{49}}\):\(\displaystyle \;\;\frac{\sqrt{2}}{7}\)
Now we have:\(\displaystyle \L \;\sqrt{2}\,+\,\frac{\sqrt{2}}{7}\)
We need like denominators to add:\(\displaystyle \;\;\frac{\sqrt{2}}{1}\,\cdot\,\frac{7}{7}\,=\,\frac{7\sqrt{2}}{7}\)
So what's \(\displaystyle \L \;\frac{7\sqrt{2}}{7}\,+\,\frac{\sqrt{2}}{7}\;\)
?