4 decks of cards: probability of dealing a 13-card hand

If 4 decks of cards are suffled together, what is the probability of dealing a 13-card hand that includes exactly 2 black card 3s?

so,

total cards 208
black cards 104

\(\displaystyle \L\frac{104C2*104C11}{208C13}\)

but i dont get the right answer with this, can someone help me with this?


Thanks

wind said:

If 4 decks of cards are suffled together, what is the probability of dealing a 13-card hand that includes exactly 2 black card 3s?

Click to expand...

Surely that mean what it says!

There are only 8 black threes in a 4-deck pile. So there are 200 others.
\(\displaystyle \L \frac{{C(8,2)C(200,11)}}{{C(208,13)}}\).

DOH!!! I miscounted and used all the 3's.

Thanks, galactus, pka