Is this Correct? (choosing 5, if exactly 3 must be seniors)

How many ways can 5 students be chosen from a group of 4 juniors and 6 seniors to be on the prom committee if exactly 3 students must be seniors?

10! / 3! 3! 4! = 604800

Is this correct or should I be doing the equation as a permutation.

\(\displaystyle { 6 \choose 3}{ 4 \choose 2} = \frac{{6!}}{{\left( {3!} \right)\left( {3!} \right)}}\frac{{4!}}{{\left( {2!} \right)\left( {2!} \right)}}\)