jane said:(6p-18/9p)/(3p-9/p^2+2p)
[6(p-3)/9p]*[p(p+2)/3(p-3)]
(2/9p)*[p(p+2)/1]
[2p(p+2)]/9p
HELP! is this correct?
BUT you posted this: (6p-18/9p)/(3p-9/p^2+2p) ; that's NOT the same thing!jane said:I did!!! Its fractions.
Fraction one is (6p-18) over 9p
that fraction is divided by 3p-9 over p squared +2p
then you have to factor it....