~N(100,256) Calculating prob. below 120

H

holdyourhorsiieees

New member
Joined
Sep 21, 2007
Messages
26
How would I calculate the probability below 120 given the mean of the normal distribution, 100, and standard deviation 16 (square root of 256)?


Thanks in advance!
 
\(\displaystyle \L\;z\;=\;\frac{120-100}{16}\;=\;1.25\)?
 
ok, i understand that is the z score. is that the answer though also? or using the ti 83 would i do normcdf(-E99,120,100,16)?
 
I think you have it correct on your TI.

If you want the other side, you need 1 - normcdf(-E99,120,100,16)

Good work.
 
You must log in or register to reply here.
Top