Three Rolls of a Single Fair Die

What is the probability that on three rolls of a single fair die at least one of the rolls will be a six?

a) 91/216
b) 108/195
c) 45/112
d) 115/216
e) 25/51

Total possible outcome = 63 = 216
6,6,1 6,6,2 6,6,3 6,6,4 6,6,5 = 5 times
6,1,6 6,2,6 6,3,6 6,4,6 6,5,6 = 5 times
1,6,6 2,6,6 3,6,6 4,6,6 5,6,6 = 5 times
TOTAL 15 times
6,6,6 = 1 time
25 + 25 + 25 = 75 WHAT IS THIS? 15 • 5 = 75 WHAT IS THIS?
75 + 15 + 1 = 91 WHERE DOES 75 COME FROM? (Please excuse the "all cap" words - I cannot use bold or underline.)

Jackie9988 said:

What is the probability that on three rolls of a single fair die at least one of the rolls will be a six?

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What is the probability that NO roll will be a "6"? The probability of "one or more throws is a '6'" is the difference between 1 and this "no sixes" value. :wink:

Jackie9988 said:

(Please excuse the "all cap" words - I cannot use bold or underline.)

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The "" and "" tags aren't working...? Do you have "BBCode" set as being "off"...? :?:

Jackie9988 said:

Total possible outcome = 63 = 216

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What does this mean? How does sixty-three equal two hundred sixteen...? :shock:

Jackie9988 said:

6,6,1 6,6,2 6,6,3 6,6,4 6,6,5 = 5 times
6,1,6 6,2,6 6,3,6 6,4,6 6,5,6 = 5 times
1,6,6 2,6,6 3,6,6 4,6,6 5,6,6 = 5 times
TOTAL 15 times
6,6,6 = 1 time
25 + 25 + 25 = 75 WHAT IS THIS? 15 • 5 = 75 WHAT IS THIS?

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I don't know. What was your reasoning? How did you generate this?

Please be complete. Thank you!

Eliz.