Princezz3286
Junior Member
- Joined
- Nov 12, 2005
- Messages
- 66
Ok, I have used this site before and it was awesome, but I am in college.... taking a refresher course and I have never been good at this stuff even in my highschool days. I have a few questions and I would like to make sure that my overall processes are correct. Here are a few problems that I am working with....
directions are Factor Completely:
9x^2 + 12x + 4
On this I would just like to confirm that it already is factored because we can't take anything out of this and it does not break down into two factors.
16a^2 - 40a + 25
On this problem, I was able to factor it down to (4a - 5) and (4a - 5) as the factors, on this I would like to know if writing it like this (4a - 5)^2 would make my answer incorrect or if this is ok
(a+b)c^2 - 5(a+b)c - 24 (a+b)
My question on this is can I eliminate all of the (a+b)'s and work with the remaining c^2 -5c - 24? If I can do that my answer is (c - 8)(c - 3)
(c +4d)^2 - (c - 4d)^2
On this problem, I broke it down into exactally what it is:
(c +4d)(c +4d) - (c - 4d)(c - 4d)
from here I put it into trinomial form:
c^2 + 8dc + 16d^2
- c^2 - 8dc + 16d^2
----------------------------------
I cancelled out the c^2 and the 8dc, well they pretty much cancelled themselves.... and I was left with 32d^2 are my procedures here correct?
I have a few more questions but I will ask those a little later, I don't want to take up too much time here as I am aware, like myself, there are many other confused students!
Thanks in advance,
Heather
directions are Factor Completely:
9x^2 + 12x + 4
On this I would just like to confirm that it already is factored because we can't take anything out of this and it does not break down into two factors.
16a^2 - 40a + 25
On this problem, I was able to factor it down to (4a - 5) and (4a - 5) as the factors, on this I would like to know if writing it like this (4a - 5)^2 would make my answer incorrect or if this is ok
(a+b)c^2 - 5(a+b)c - 24 (a+b)
My question on this is can I eliminate all of the (a+b)'s and work with the remaining c^2 -5c - 24? If I can do that my answer is (c - 8)(c - 3)
(c +4d)^2 - (c - 4d)^2
On this problem, I broke it down into exactally what it is:
(c +4d)(c +4d) - (c - 4d)(c - 4d)
from here I put it into trinomial form:
c^2 + 8dc + 16d^2
- c^2 - 8dc + 16d^2
----------------------------------
I cancelled out the c^2 and the 8dc, well they pretty much cancelled themselves.... and I was left with 32d^2 are my procedures here correct?
I have a few more questions but I will ask those a little later, I don't want to take up too much time here as I am aware, like myself, there are many other confused students!
Thanks in advance,
Heather