Re: Algebra
Missy said:
the instructions are to solve the equation algebraically
and the problem is 3/4 =1-3x-2 / x + 1
Being out of school for some thirty years I need all the help I can with Alegebra
Does your problem look as follows (somewhat):
\(\displaystyle solve \, algebraically:\)
\(\displaystyle \frac{3}{4}\, = \, \frac {1\, - \, 3x \, - \, 2}{x\, + \, 1}\)
If it does:
Since both sides contain fractions, my preference (strictly preference - not a rule) - is to get rid of the fraction by multiplying with the LCD (considering all the denominators from both sides of = sign)
In this case it is 4 * (x+1). So:
\(\displaystyle \frac{3}{4}\, = \, \frac {1\, - \, 3x \, - \, 2}{x\, + \, 1}\)
\(\displaystyle 4\cdot ( x\, + \, 1) \cdot \frac{3}{4}\, = \, 4\cdot ( x\, + \, 1) \cdot \frac {-1\, - \, 3x }{x\, + \, 1}\)
After eliminating common factors
\(\displaystyle ( x\, + \, 1) \cdot 3\, = \, 4\cdot (-1\, - \, 3x)\)
Now simplify above by multiplying - isolate 'x' - and solve.