Factoring; quadratic formula

Belanova said:
2x^2 + 8x + 8 = 0

48q^2 + 168q +147 = 0


You didn't indicate your directions for these. I'll assume you're trying to SOLVE each equation for the variable involved.

A good suggestion is to see if you can divide each term by a common factor.

In your first equation, you can divide each term by 2. When you do that, you get

x[sup:wf4a3hae]2[/sup:wf4a3hae] + 4x + 4 = 0
Now, that should be fairly easy to factor, or you can use the quadratic formula.

For the second equation, you can divide each term by 3:
16q[sup:wf4a3hae]2[/sup:wf4a3hae] + 56q + 49 = 0
Again, that should be fairly easy to factor...hint: it's the square of a binomial.

If you're still having trouble, please repost, showing all of the work you've done to attempt a solution. We can help best if we see your work so we can tell where your difficulties lie.
 
Your subject line says "factoring; quadratic formula". Does this mean that the instructions (not included within your post) were to "solve by factoring or by applying the Quadratic Formula"? Or were they something else? And how far have you gotten? (Since the Quadratic Formula will solve any quadratic, you obviously can make a lot of progress using this method, so clearly you have work that you can show us.)

Please be complete. Thank you! :D

Eliz.
 
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