Solving Quadratic Equations by Graphing

jramirez23

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Jan 23, 2008
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I have to graph the following equation in order to determine the number of solutions it has.

-x[sup:2nm83z6o]2[/sup:2nm83z6o]+-4x= 5

Negative x to the second power plus negative 4x is equal to 5.

I got to the point where I found the vertex of the equation, which happens to be -2. I then attempted to make a table of values. I then decided to find the y-coordinate of the vertex. But this is where I'm stuck. I THINK that I have to put my equation into an original form that would be something like this:

-x[sup:2nm83z6o]2[/sup:2nm83z6o] +-4x +-5 = y
(I think this is the next step and I need to confirm that that really is the next step.

I need a walkthrough for this problem please.
 
The first thing I would do is multiply both sides of the equation by -1. Then get all terms on one side of the equation and set the trinomial = y. Now, I'm ready to graph it.
 
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