Use the quotient property to simplify the expression.

S

slytheringirl11279

New member
Joined
Feb 26, 2008
Messages
19
If anyone can help me i would be so thankful

so i have the problem 5 square root 13 over 25 and the answer i got was 5 square root 13 over 5 if that right
 
I don't think that's right, because simplifying means that you just make the number or equation or whatever it is simpler, it shouldn't change the value of the "thing" being simplified.

For example, the exact value of your original problem was (approximately):

(5 * sqrt(13)) / (25) = 0.7211

after you "simplified" it, you got:

(5 * sqrt(13)) / (5) = 3.605

clearly, you must not have simplified correctly, because the two values aren't the same. I'm not sure what the "quotient property" is, but I do know you can simplify the 5/25 in your problem to 1/5, because both values equal 0.2! So, if you simplified it, you would get:

(sqrt(13)) / (5) , which equals: 0.7211 - meaning you simplified correctly!

http://tinyurl.com/2l9oql

Try simplifying these (to fractions, not decimals):

5/25

3/9

6/24

72/81

1/4

6/3

Hope this helps and that I didn't give you any wrong information!
 
HELP

ok so the problem was 5 then the square root symbool then 13 / 5 now i got the answer 5 square root symbool then 13 / 5 is that even close
 
it si me again

ok my bad for the one before i mean 5 square root symbool 13 / 25 and i got 5 square root symbool 13 / 5
 
Re: HELP

I think the problem was:

5 * (sqrt(13/25))

you can bring the 5 into the sqrt by multiplying it by itself, so:

sqrt(13/25 * (5*5))

5 * 5 is 25, right?

so now you have:

sqrt( (13*25) / 25)

the 25's cancel out to 1, so you get:

sqrt(13) which should be equal to your original problem

http://tinyurl.com/37t3sy
 
Re: HELP

my work was 5 square root thingy 13/25 then i broke down 25 and got 5 square root thingy 13/5*5 and the fives cancle out so i was left with 5 square root thingy 13 is that my answer i put the five under the 13 cause it maked one or something like that
 
Re: HELP

Okay look, if you have a number times itself inside a sqrt, you can bring it out as itself. For example:

sqrt(25) = sqrt(5 * 5) = 5

right?

so if you have:

sqrt(1/25) = sqrt((1/5)*(1/5)) = (1/5)

right?

So now you just have a 13 over the (1/25), meaning you can take out the (1/25), but not the 13, because there is no perfect, integer square root of 13. When you take out the (1/25) as (1/5), the 5 * (1/5) cancels out to 1, leaving you with 1 * (sqrt(13)). Get it?
 
Re: HELP

so my answer is 13? My teacher yells at us if the problem is a fraction and we dont have a fraction answer does this pratain to this problem

Also i need help with

find the area of the figgure
it is a rectangle and one side is square root 3 and the other is square root 16 i got some how square root 6. Is that right
 
Re: HELP

No, your answer would be sqrt(13), which is not a fraction - go back and try to figure out what I did to arrive at that answer. I don't have time to work the area problem right now; someone else may help you though. Good luck with it!
 
Re: HELP

okay the other one doesn't take that long:

the formula for the area of a rectangle is length * width, right?

So your length is sqrt(3), your width is sqrt(16) - or vice versa, it doesn't matter too much here.
So you have to multiply those together, but first you can simplify one of them:

16 = 2 * 2 * 2 * 2

you can take two sets of 2 out of the sqrt, making sqrt(16) equal to 2 * 2, which is 4. So, now multiply your length times your width:

sqrt(3) * 4 = 4*sqrt(3)

which is your answer. I really gotta go now - hope this helps somewhat and that you figure it out.
 
slytheringirl11279 said:
5 square root 13 over 25 and the answer i got was 5 square root 13 over 5 if that right
Click to expand...
Your formatting is sufficiently ambiguous as to make the answer uncertain. Sorry! :oops:

Kindly please review the formatting articles in the links you noted in the "Read Before Posting" thread that you read before posting. Then please reply with clarification, including all of your work and reasoning.

Please be complete. Thank you! :D

Eliz.
 
slytheringirl11279 said:
If anyone can help me i would be so thankful

so i have the problem 5 square root 13 over 25 and the answer i got was 5 square root 13 over 5 if that right
Click to expand...

If what you mean is this:

5 * sqrt(13/25)

then, you can rewrite it as

5 * [sqrt(13) / sqrt(25)]

or,

5*[sqrt(13)] / 5

or,

sqrt(13)
 
slytheringirl11279 said:
ok 5sqrt(13/25)
i broke down 25 in to 5*2 so it looks like 5sqrt(13/5*5) but now i am stuck
Click to expand...


Ok...

now you have

sqrt(13) / sqrt(5*5)

or,

sqrt(13) / 5
 
Re: problem

slytheringirl11279 said:
5srqt13/25
now my answer is 5sqrt13/5 is that rite
Click to expand...

No...

you had

5 sqrt(13/25)

rewrite sqrt(13/25) as sqrt(13) / sqrt(25), or sqrt(13) / 5

Now you have

5 * [sqrt(13) / 5]

or,

sqrt(13)
 
You must log in or register to reply here.
Top