poisonroxs

04-12-2008, 04:08 PM

I have done this problem, however I do not feel confident in my answer, can anyone confirm if it is correct?

$1 lottery ticket

Lottery draws 5 out of 55 white balls (1 of 55 inclusive)

and 1 out of 42 for the powerball (1 of 42 inclusive)

How much would you have to spend to play all of the possible winning combinations to be sure you would win?

nCr

n=55

r=5

n!/r! (n-r)!

55!/5! (50)!

(5!)^2 (50!)^2/(5! 55! (45+5)! (5-5)!^2 *1/42

55 X 54 X 53 X 52 X 51/5 X 4 X 3 X 2 X 1

120/55 x 54 x 53 x 52 x 51x 42 =

1 out of 146,107,962 chance of winning with buying 1 ticket so you would have to spend $146,107,962 to play all possibilities, which is stupid because no lottery prize is that high.

Any feedback would be greatly appreciated :D

$1 lottery ticket

Lottery draws 5 out of 55 white balls (1 of 55 inclusive)

and 1 out of 42 for the powerball (1 of 42 inclusive)

How much would you have to spend to play all of the possible winning combinations to be sure you would win?

nCr

n=55

r=5

n!/r! (n-r)!

55!/5! (50)!

(5!)^2 (50!)^2/(5! 55! (45+5)! (5-5)!^2 *1/42

55 X 54 X 53 X 52 X 51/5 X 4 X 3 X 2 X 1

120/55 x 54 x 53 x 52 x 51x 42 =

1 out of 146,107,962 chance of winning with buying 1 ticket so you would have to spend $146,107,962 to play all possibilities, which is stupid because no lottery prize is that high.

Any feedback would be greatly appreciated :D