View Full Version : Probability of 2 independent variables

poisonroxs

04-12-2008, 05:08 PM

Is this correct?

A certain airplane has two independent alternators to provide elecrical power. The probability that a given alternator will fail on a 1 hour flight is .02. What is the probability that

a) both will fail?

b) neither will fail?

C) One or the other will fail?

A) P(x=2) .02*.02= .0004 or 4%

B) P(x=0) 1-0.02=.98

(.98*.98)= .09604 or 9.6%

C) P(x=1) 2(.98)(.02)=.0392 or 3.9%

Thanks for any input in advance :o)

Subhotosh Khan

04-12-2008, 05:29 PM

Is this correct?

A certain airplane has two independent alternators to provide elecrical power. The probability that a given alternator will fail on a 1 hour flight is .02. What is the probability that

a) both will fail?

b) neither will fail?

C) One or the other will fail?

A) P(x=2) .02*.02= .0004 or 0.04%

B) P(x=0) 1-0.02=.98

(.98*.98)= 0.9604 or 96%

C) P(x=1) 2(.98)(.02)=.0392 or 3.9%

Thanks for any input in advance :o)

poisonroxs

04-12-2008, 05:38 PM

Sorry but I do not understand your post. What do the red marks mean, are they incorrect?

stapel

04-12-2008, 07:13 PM

What do the red marks mean, are they incorrect?

Compare what you'd posted with what the tutor posted; in particular, compare the tutor's red-highlighed text with your corresponding black text. While doing so, recall that the total of the probabilities, since they cover all possible cases, should add up to 100%. What total do your values give? What total do the tutor's values give? :wink:

Eliz.

poisonroxs

04-12-2008, 07:33 PM

so this is how I should present my answer?

A) .0004

B) .9604

C) .0392

this all added together equals 1

Thank you in advance

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