help please: (6/9-a^2)-(3/12+4a)

Re: help please!?

(6/9-a^2)-(3/12+4a) means...

\(\displaystyle (\frac{6}{9}-a^2)-(\frac{3}{12}+4a)\)

Is that what you mean?

If so, the first step would be to reduce the fractions to lowest terms.
 
martanks said:
(6/9-a^2)-(3/12+4a)
Click to expand...
Are you supposed to simplify this? Evaluate this for some given value of "a"? Find asymptotes? Find the domain? Or something else? How far have you gotten?

Please be complete. Thank you! :D

Eliz.
 
If you set that expression equal to f(a), it won't have asymptotes, will it? It's a parabola.
 
masters said:
If you set that expression equal to f(a), it won't have asymptotes, will it? It's a parabola.
Click to expand...
If the poster meant "[(1/3) - a[sup:2gv707pj]2[/sup:2gv707pj]] - [(1/4) + 4a] = (1/12) - 4a - a[sup:2gv707pj]2[/sup:2gv707pj]", then it will be a parabola. But what the poster provided would be an extremely odd way ever to format a parabola. :shock:

It's not impossible that a parabola might be presented this way, of course, but the stronger likelihood is that the poster actually meant something else, probably along the lines of a rational expression or function. :wink:

Unfortunately, we're stuck just guessing until the poster replies with the requested information. :oops:

Eliz.
 
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