math project: int[(1+x^2)/x]dx, (3+x)/[(1-x)(1+3x)] in part.

C

carlasader

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hi everyone i have attached my math project because i need help in solving it and i dont know where to start from ...need urgent help[attachment=0:20klnpnh]scan0005.jpg[/attachment:20klnpnh]
 

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carlasader said:
i have attached my math project because i need help in solving it and i dont know where to start from
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I'm sorry, but this material is so far past "Beginning Algebra" that I'm afraid there is no possible way to explain this to you in just a forum posting. You need to finish your current algebra course, take a few more, take trigonometry, and then take a course or two of calculus. By that point, this can be explained.

Pretty harsh "project", if you ask me.... :shock:

Eliz.

P.S. For those unable to view the image, the scanned text is as follows:

3-a) Find int [1,illegible] [ (1 + x^2) / x ] dx.

3-b) Express f(x) = (3 + x) / [ (1 - x)(1 + 3x) ] in partial fractions.

3-c) Hence, find int [0, illegible] [ f(x) ] dx.

Given: f(x) = (x + 4) / [ (x + 1)[sup:2ew98azy]2[/sup:2ew98azy] (x + 2) ].

4-a) Express f(x) as A / (x + 1)[sup:2ew98azy]2[/sup:2ew98azy] + B / (x + 1) + C / (x + 2), and find the values of A, B, and C.

4-b) Evaluate f'(1), giving your answer as an exact rational number.

The finite region R is bounded by the curve y = f(x), the coordinate axes, and the line x = 3.

4-c) Find the area of R, giving your answer in the form "p + ln(q)", and find the values of p and q.
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Q3a. Split the equation up and integrate (1/x = In(x))

Q3b. Do you have a formula sheet?

( px + q ) / ( (ax + b)(cx + d) ) = A / (ax + b) + B / (cx + d)

Cross multiply to get (px + q) = A(cx + d) + B(ax + b), then just make x be something to eliminate A or B to find them both.

Q3c. Integrate that answer.


Q4. Check your formula sheet!
 
markbrock30 said:
...integrate (1/x = In(x))

( px + q ) / ( (ax + b)(cx + d) ) = A / (ax + b) + B / (cx + d)

...Integrate that answer.
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Okay, but now you need to explain partial-fraction decomposition and integration to this elementary-algebra student.

popcorn.gif


Eliz.
 
elementary-algebra student
Click to expand...

We have a beer called Tui over here in New Zealand...

The beer's advertising campaign consists of statements followed by - Yeah Right...


E.g. The person who posted this is doing elementary level math - Yeah Right....

:lol: :lol:
 
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