Discrete Random Variables: Find P(5) for P(X) = 0.23(0.77)x-

I NEED HELP WITH THIS PROBLEM

QUESTION: A WEAPONS MANUFACTURER USES A LIQUID PROPELLANT TO PRODUCE GUN CARTRIDGES. DURING THE MANFACTURING PROCESS, THE PROPELLANT CAN GET MIXED WITH ANOTHER LIQUID TO PRODUCE A CONTAMINATED CARTRIDGE. A UNIVERSITY OF SOUTH FLORIDA STATISTICAN, HIRED BY THE COMPANY TO INVESTIGATE THE LEVEL OF CONTAMINATION IN THE STORED CARTRIDGES, FOUND 23% OF THE CARTRIDGES IN A PARTICULAR LOT WERE CONTAMINATED. SUPPOSE YOU RANDOMLY SAMPLE (WITHOUT REPLACEMENT) GUN CARTRIDGES FROM THIS LOT UNTIL YOU FIND A CONTAMINATED ONE.
LET X BE THE NUMBER OF CARTRIDGES SAMPLED UNTIL A CONTAMINATED ONE IS FOUND. IT IS J=KNOWN THAT THE PROBABILITY DISTRIBUTION FOR X IS GIVEN BY THE FORMULA.

P(X)=(.23)(.77)x-1, X=1,2,3

B. FIND P(5) INTERPRET THE RESULT
C. FIND P(X GREATER THAN OR EQUAL TO 2) INTERPRET THE RESULT

Re: DISCRETE RANDOM VARIBLES

I don’t understand. You seem to be asking us to do the calculations for you?
Don’t you have a calculator that you know how to use?
Have I misread your question?