Please help, i dont even know where to start: L-4(2/x-2)^2

To find the image length, L, of a 4-foot-tall object in a spherical mirror with a focal length of 2 feet, L-4(2/x-2)^2 can be used, where x is the distance, in feet, of the object from the mirror. What is the image length of the object when it is 1.5 feet away from the mirror?

Re: Someone please help, i dont even know where to start. ]]:

lovexthatkid said:

To find the image length, L, of a 4-foot-tall object in a spherical mirror with a focal length of 2 feet, L-4(2/x-2)^2 can be used, where x is the distance, in feet, of the object from the mirror. What is the image length of the object when it is 1.5 feet away from the mirror?

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1) You simply MUST write carefully. Can we assume you meant to write an equation? Image Length = L - 4(2/(x-2))^2 In this equation, L cannot be the image length.

2) You are given the height of the object, 4 ft = L. This results in Image Length = 4 - 4(2/(x-2))^2

3) You are given the distance, x = 1.5 ft. This results in Image Length = 4 - 4(2/(1.5-2))^2

4) I'm just guessing what you mean and it really makes little sense to me. You must present the ENTIRE problem statement EXACTLY as it is worded.

5) I believe you have no idea where to start. It appears you are trying to do a review without ever actually looking at the material. This is not encouraging.