Setting up perim. word prob. (lot w/ fencing on 3 sides)

hurlgyrl

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Jul 8, 2008
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How do I set up the equation(s) for the following word problem:

A rectangular lot whose perimeter is 360 feet is fenced along 3 sides, the 4th side is along a wall and doesn't need to be fenced. Expensive fencing along the length of the lot is $20 per foot. Inexpensvie fencing along the widths cost $8 per foot. The total for all 3 sides is $3280. What are the dimensions of the lot?

Thank you for your help. Whatever you can give is appreciated.
 
Re: Setting up a perimeter word problem

Draw a sketch. Label the length of the lot x (feet) and the width of the lot y (feet).
It tells you that the perimeter of the lot is 360 ft. That should be the basis of one equation.
For the second equation you have to think in terms of cost. If the price of the fencing used in the length is $20 per foot then the cost of the length is 20x (dollars). Figure the cost of the two widths in terms of y and use these figures to build the equation knowing that the total cost is $3280.
You should end up with two equations in two unknowns that are easily solved.
If you need more help, show us what you have done so far so we can determine where you need help.
 
Re: Setting up a perimeter word problem

x = side length along wall
y = other side length

2x + 2y = 360 [1]

20x + 2(8y) = 3280 [2]
 
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