graph corner points for feas. region: x>3, y>2, x+y<10, and

can anybody help me calculate corner points for this question? i have a very hard time with these. most of the examples i have talk about substituting 0 for x and y, but this problem show x is greater than or equal to 3 and y is greater than or equal to 2. which way do i go with this. Any help would be greatly appreciated.

also i must note that the < and > symbols are underlined, i just couldn't get the underline to show in the equation on this page. thanks

Determine the coordinates of every point for the feasible region defined by the following inequalities: x>3; y>2; x + y < 10; 2x+3y < 24

Re: graphing corner points

1) Ignore the ">" and ">=" signs.
2) Graph the equations using any method available to you.
3) Remember the ">" and ">=" signs.
4) Test each side of each line. If it works in the INequality, shade that side.
5) Think about whether it matters of ryour particular problem if is is ">" or ">=". It may not. Obviously, if an intersection is not in the feasible region, why would it matter?