DarkLightA
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- Nov 9, 2008
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It sais x^3+1 can be factored to (x+1)(x^2-x+1). I don't get how you work this out though!?
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Factoring x^3 + 1: how do they get (x + 1)(x^2 - x + 1)?
- Thread starter DarkLightA
- Start date
D
Deleted member 4993
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Re: Factoring x^3+1?
There is a standard formula:
\(\displaystyle a^3 \, + \, b^3 \, = \, (a \, + \, b)\cdot (a^2 \, - \, a\cdot b \, + \, b^2)\)
edit: fixed the sign problem - thanks wjm
DarkLightA said:It sais x^3+1 can be factored to (x+1)(x^2-x+1). I don't get how you work this out though!?
There is a standard formula:
\(\displaystyle a^3 \, + \, b^3 \, = \, (a \, + \, b)\cdot (a^2 \, - \, a\cdot b \, + \, b^2)\)
edit: fixed the sign problem - thanks wjm
fasteddie65
Full Member
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- Nov 1, 2008
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- 360
Re: Factoring x^3+1?
BTW, you should commit this to memory, as well as x^3 - 1 = (x - 1)(x^2 + x + 1)
BTW, you should commit this to memory, as well as x^3 - 1 = (x - 1)(x^2 + x + 1)