1/(2x) + 1/(3x) = x/(3)

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Panama

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Without actually solving the equation list all possible numbers that would be rejected if they appeared as potential solutions


1/(2x) + 1/(3x) = x/(3)



I think the answer is 0. Is this correct?
 
Panama said:
Without actually solving the equation list all possible numbers that would be rejected if they appeared as potential solutions


1/(2x) + 1/(3x) = x/(3)



I think the answer is 0. Is this correct? <<<< Correct
Click to expand...

As x increases - the left-hand-side(LHS) decreases but the right-hand-side(RHS) increases.

At x=3, quick mental math tells you that RHS is way bigger. So |x|<3 is an approximate bound on the value of x.
 
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