letsgetaway
New member
- Joined
- Jul 16, 2006
- Messages
- 44
I don't understand how to find a proportion.
Homework Question: A distribution of measurements is mound-shaped with mean 50 and standard deviation 10. What proportion of the measurements will fail between 30 and 60?
I've calculated how many deviations from the mean.
50 +/- 10 = 40, 60 -- 68% (using empirical rule)
50 +/- 2(10) = 30, 70 -- 95% (using empirical rule)
I don't know my next step to find this proportion since it spans through both directions from the mean.
|---30---40---50(mean)---60---70
So is my logic correct in thinking that I should...
30 to 50 is half of 95%. 50 to 60 is half of 68%.
47.5% + 34.0% = 81.5%
Homework Question: A distribution of measurements is mound-shaped with mean 50 and standard deviation 10. What proportion of the measurements will fail between 30 and 60?
I've calculated how many deviations from the mean.
50 +/- 10 = 40, 60 -- 68% (using empirical rule)
50 +/- 2(10) = 30, 70 -- 95% (using empirical rule)
I don't know my next step to find this proportion since it spans through both directions from the mean.
|---30---40---50(mean)---60---70
So is my logic correct in thinking that I should...
30 to 50 is half of 95%. 50 to 60 is half of 68%.
47.5% + 34.0% = 81.5%