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James2

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Oct 14, 2009
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8
Hi,
Can anybody help me with this please.

a[sup:4sxcgxpm]3[/sup:4sxcgxpm]b[sup:4sxcgxpm]2[/sup:4sxcgxpm]c[sup:4sxcgxpm]4[/sup:4sxcgxpm]
abc[sup:4sxcgxpm]-2[/sup:4sxcgxpm]

I hope it makes sense. I think the answer may be this.

a[sup:4sxcgxpm]2[/sup:4sxcgxpm]b c[sup:4sxcgxpm]6[/sup:4sxcgxpm]
 
James2 said:
Hi,
Can anybody help me with this please.

a[sup:34k13dkx]3[/sup:34k13dkx]b[sup:34k13dkx]2[/sup:34k13dkx]c[sup:34k13dkx]4[/sup:34k13dkx]
abc[sup:34k13dkx]-2[/sup:34k13dkx]

I hope it makes sense. I think the answer may be this.

a[sup:34k13dkx]2[/sup:34k13dkx]b c[sup:34k13dkx]6[/sup:34k13dkx]
Click to expand...

Hi James2,

\(\displaystyle \frac{a^3b^2c^4}{abc^{-2}}=a^2bc^6\)

Your answer is correct.
 
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