Hi. I have math 17 aka logic as a class, and the teacher is gone half the time so I can't speak to him. I can't figure out the answer to (x-2y)^5. I wrote the problem out into five times. Also, saying for y would the exponets i -2 fives time to an answer? Help is appericated, and thanks.
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Binomial Theorem problem
- Thread starter alainea
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arthur ohlsten
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- Feb 20, 2005
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[a+b]^5=a^5 + 5a^4b +10a^3b^2 + 10a^2b^3 + 5a b^4 +b^5
a=x
b=-2y
Arthur
a=x
b=-2y
Arthur
WHAT does that mean? Can you be clear, please.alainea said:Also, saying for y would the exponets i -2 fives time to an answer?
arthur ohlsten
Full Member
- Joined
- Feb 20, 2005
- Messages
- 852
[a+b]^5=a^5+5a^4b+10a^3b^2+10a2b^3+5ab^4+b^5
let a=x
let b=-2y
[x-2y]=x^5+5x^4(-2y) +10x^3(-2y)^2+10x^2(-2y)^3+5x(-2y)^4+(-2y)^5
you can finish the problem
Arthur
let a=x
let b=-2y
[x-2y]=x^5+5x^4(-2y) +10x^3(-2y)^2+10x^2(-2y)^3+5x(-2y)^4+(-2y)^5
you can finish the problem
Arthur