ewainright
New member
- Joined
- Nov 10, 2009
- Messages
- 3
if f(x)=4x-5 and g(x)=x^2+1, find each value
if g(t)-4
if f(3a^2)
would the answer be
f(t)=4(t)-5 and g(t)=t^2+1
f(3a^2)=4(3a^2)-5 and g(3a^2)=(3a^2)^2+1
if g(t)-4
if f(3a^2)
would the answer be
f(t)=4(t)-5 and g(t)=t^2+1
f(3a^2)=4(3a^2)-5 and g(3a^2)=(3a^2)^2+1
