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algerba
- Thread starter rrolo31
- Start date
rrolo31 said:cannot solve please help
x2/x-3=x2/1x3=(x2)(x3)=x3
What's this !
Please type clearer .
Helolo, rrolo31!
Even with my wildest guessing, it doesn't make any sense . . .
\(\displaystyle \frac{x^2}{x}-3 \;=\;\frac{x^2}{1x^3} \;=\;(x^2)(x^3) \;=\;x^3\)
\(\displaystyle \frac{x^2}{x-3} \;=\;\frac{x^2}{1\times3} \;=\;(x^2)(x^3) \;=\;x^3\)
What is the equation ?
cannot solve please help
x2/x-3=x2/1x3=(x2)(x3)=x3
Even with my wildest guessing, it doesn't make any sense . . .
\(\displaystyle \frac{x^2}{x}-3 \;=\;\frac{x^2}{1x^3} \;=\;(x^2)(x^3) \;=\;x^3\)
\(\displaystyle \frac{x^2}{x-3} \;=\;\frac{x^2}{1\times3} \;=\;(x^2)(x^3) \;=\;x^3\)
What is the equation ?