maths_arghh234
Junior Member
- Joined
- Nov 8, 2009
- Messages
- 52
the second part c of a question that i'm stuck on
here's the question -
in a computer simulation 500 dots were fixed at a target and the probability of a dot hitting the target was 0.98. find the probability that
a) all the dots hit the target b) at least 495 hit the target ..
in the previous question i said x = the number of left handed people not the number of right handed .... so in this one i did the same method and i let X be the number of dots that didn't hit the target so in a
x = 0 which = 4.5x 10-3
but b. at least 495 hit the target .. which mean 496, 497, 498, 499 or 500 could've hit the target right ? ... so X < or equal to 5 right ... which is x=0 +x=1 +x=2+x=3+x=4 +x=5 i tried that but the answer come out wrong so i'm assuming i've done something wrong but i dunno what
here's the question -
in a computer simulation 500 dots were fixed at a target and the probability of a dot hitting the target was 0.98. find the probability that
a) all the dots hit the target b) at least 495 hit the target ..
in the previous question i said x = the number of left handed people not the number of right handed .... so in this one i did the same method and i let X be the number of dots that didn't hit the target so in a
x = 0 which = 4.5x 10-3
but b. at least 495 hit the target .. which mean 496, 497, 498, 499 or 500 could've hit the target right ? ... so X < or equal to 5 right ... which is x=0 +x=1 +x=2+x=3+x=4 +x=5 i tried that but the answer come out wrong so i'm assuming i've done something wrong but i dunno what