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ticka06

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Joined
Jan 29, 2010
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6
8. The number of accidents that occur at the intersection
of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
 
Well, graph it.

Expected Value = \(\displaystyle \sum x\cdot p(x)\). Add them up. There's only 4.

0*0.84+ 1*0.13 + 2*0.02 + ... You're not going to make me do ALL the work, are you?
 
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