Can anyone help me this question,please.

LincolnH

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Sep 28, 2010
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Can anyone check for me?
In a class, 80 students were interviewed about the newspapers they read daily. The 3 newspapers ‘N1’, ‘NE’ and ‘Star’ were under survey. The results are as follows:
36 read ‘N1’, 40 read ‘NE’, 28 read ‘Star’, 17 read both ‘N1’ and ‘NE’, 14 read both ‘NE’ and ‘Star’, 18 read both ‘N1’ and ‘Star’, and 10 read all three newspapers.

If we select a student at random, what is the probability that
(i) the student reads ‘NE’ and ‘Star’?
(iii) the student reads ‘N1’, given that the student reads ‘NE’?

This my wrong answer that I tried:
After drawing a venn diagram. I got 11 for N1,19 for NE,6 for star,8 for N1 and star,7 for N1 and NE,4 for NE and star and 10 for all newspaper.But 15 students don't read any newspapers

i.)P(NE and Star)=14/80
=7/40

ii.)P(NE|N1)/P(N1)
=(11/80)/(19/80)
=11/19
 
The first one would be 14/65, would it not?.

The second one \(\displaystyle P(NE|N1)=\frac{P(N1 \;\ and \;\ NE)}{P(NE)}=\frac{17}{40}\)
 
galactus said:
The first one would be 14/65, would it not?.

The second one \(\displaystyle P(NE|N1)=\frac{P(N1 \;\ and \;\ NE)}{P(NE)}=\frac{17}{40}\)


I don't understand how to get 14/65.Can you please show the steps,Please?
 
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