Sum of two dice

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eeekie

New member
Joined
Oct 7, 2010
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2
Okay, so basically it says someone rolls two dice and its asking about the probability of rolling certain sums of the two dice.
the probability of the sum being:
2 is 1/36
3 is 2/36
4 is 3/36
5 is 4/36
6 is 5/36
7 is 6/36
8 is 5/36
9 is 4/36
10 is 3/36
11 is 2/36
12 is 1/36
It then asks:
P(the sum of the two dice equals 2)
P(the sum of the two dice equals 7)
P(the sum of the two dice equals 10)
P(the sum of the two dice equals 6)
P(the sum of the two dice is at most 5)
P(the sum of the two dice is at least 10)
When I tried them all I just found the decimals and the website said it was wrong, I really don't know what I'm doing...
 
eeekie said:
Okay, so basically it says someone rolls two dice and its asking about the probability of rolling certain sums of the two dice.
the probability of the sum being:
2 is 1/36
3 is 2/36
4 is 3/36
5 is 4/36
6 is 5/36
7 is 6/36
8 is 5/36
9 is 4/36
10 is 3/36
11 is 2/36
12 is 1/36
It then asks:
P(the sum of the two dice equals 2)
P(the sum of the two dice equals 7)
P(the sum of the two dice equals 10)
P(the sum of the two dice equals 6)
P(the sum of the two dice is at most 5)
P(the sum of the two dice is at least 10)
When I tried them all I just found the decimals and the website said it was wrong, I really don't know what I'm doing...
Click to expand...

Can you please put the exact question - with your work?

I do not quite understand what you were supposed to do and what you had done.
 
Suppose you roll a pair of fair, six-sided dice. Compute the following theoretical probabilities. Round to the nearest thousandth, if necessary. Hint: Use the following addition table to see all of the possible outcomes when rolling a pair of fair, six-sided dice and the corresponding sum in each case. (Which is just the list of sums)

I really didn't show any work because I really didn't know what I was doing...I thought just dividing the number of possibilities by the number of possible outcomes was how I was supposed to do it but the program marked it wrong.
 


Showing your work includes the answers you got. We still do not know what you entered into the machine.

I mean, if you tried all eleven numbers, and your machine-teacher rejected them all, either you entered something incorrectly or the machine's programming is faulty.

The given hint suggests to me that you are supposed to enter a decimal number, rounded to three places.

Let's look at the first one:

P(the sum of the dice is 2)

They gave you this probability; it's 1/36.

The decimal form of 1/36 is a repeating decimal number:

0.027777777777777777777777777777777777…

Rounded to the nearest thousandth, the answer is: 0.028

Does your machine-teacher reject 0.028 ?

 
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