needtoknowmath
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I am an even, 4- digit number that has more ones than tens. My thousands digit is the quotient 9 divided by 3 and my tens digit is the sum of 3 and 3. I have no hundreds. What number am I?
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problem solving (math)
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needtoknowmath said:I am an even, 4- digit number that has more ones than tens. My thousands digit is the quotient 9 divided by 3 and my tens digit is the sum of 3 and 3. I have no hundreds. What number am I?
The digit in the ones- location must be 0 or 2 or 4 or 6 or 8.
Please show us your work indicating exactly where you are stuck - so that we may know where to begin to help you.
needtoknowmath
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i would show you my work, but thats the point i do not understand where to begin
:?
:?
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Subhotosh Khan said:needtoknowmath said:I am an even, 4- digit number that has more ones than tens. My thousands digit is the quotient 9 divided by 3 and my tens digit is the sum of 3 and 3. I have no hundreds. What number am I?
The digit in the ones- location must be 0 or 2 or 4 or 6 or 8.
Please show us your work indicating exactly where you are stuck - so that we may know where to begin to help you.
What is quotient of 9 divided by 3
What is the sum of 3 and 3?
Hello, needtoknowmath1
Do you really need help with this problem?
Exactly where is your difficulty?
We have a four-digit even number: .\(\displaystyle \square \;\square\;\square\;\square\)
. . The last (rightmost) digit is even: 0, 2, 4, 6, or 8.
The thousands digit is: \(\displaystyle }9 \div 3 = 3\)
The hundreds digit is: \(\displaystyle 0\)
The tens digit is: \(\displaystyle 3 + 3 = 6\)
. . The number is: .\(\displaystyle 3\,0\,6\,\square\)
There are more ones than tens.
The only even digit greater than 6 is \(\displaystyle 8.\)
. . Therefore, the number is: .\(\displaystyle 3\,0\,6\,8\)
Do you really need help with this problem?
Exactly where is your difficulty?
I am an even 4- digit number that has more ones than tens.
My thousands digit is the quotient 9 divided by 3 and my tens digit is the sum of 3 and 3.
I have no hundreds. .What number am I?
We have a four-digit even number: .\(\displaystyle \square \;\square\;\square\;\square\)
. . The last (rightmost) digit is even: 0, 2, 4, 6, or 8.
The thousands digit is: \(\displaystyle }9 \div 3 = 3\)
The hundreds digit is: \(\displaystyle 0\)
The tens digit is: \(\displaystyle 3 + 3 = 6\)
. . The number is: .\(\displaystyle 3\,0\,6\,\square\)
There are more ones than tens.
The only even digit greater than 6 is \(\displaystyle 8.\)
. . Therefore, the number is: .\(\displaystyle 3\,0\,6\,8\)
needtoknowmath
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Thank you, i reallly try to put my work on the posts if i understand it. But i just simply had no clue. Arthimetic was not a subject i did well in. I thank you again! But i will always try.