Probability Problem

This is the problem: 5 cards are dealt from 2 standard decks - what's the probability of being dealt 3 kings?

Using a calculator, I calculated the number of ways to draw the hand p(3 kings) as follows: 3C3 X 101C2 = 5050 (the numerator)
then I calculated the number of ways to draw 5 cards fom 2 standard decks as follows: 104C5 = 91,962.520 (the denominator)
5050/91962520 = 1/18210.4=0.00005.491 - the answer in the back of the book is .00277. where did I go wrong?

much gratitude for your assistance!

3C3 = 1

This should have clued you in to the error.

There are 8 kings.

Try 8C3 and adjust from there.

Thanks! youre right, it worked!