-3(x^2y^3) (-4xy^4)/2xy^2 = +12xy^4 - 3xy^/ 2xy^2?
P Psychguy98 Junior Member Joined Dec 17, 2010 Messages 147 Dec 31, 2010 #1 -3(x^2y^3) (-4xy^4)/2xy^2 = +12xy^4 - 3xy^/ 2xy^2?
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Dec 31, 2010 #2 Psychguy98 said: -3(x^2y^3) (-4xy^4)/2xy^2 = Click to expand... Assuming: -3(x^2 y^3) (-4x y^4) / (2xy^2 ) Do numerator first: -3(x^2 y^3) (-4x y^4) = 12 x^3 y^7 So you now have: 12 x^3 y^7 / (2 x y^2) I think you can finish that off (after what Galactus told you!) Happy new year, PG :wink:
Psychguy98 said: -3(x^2y^3) (-4xy^4)/2xy^2 = Click to expand... Assuming: -3(x^2 y^3) (-4x y^4) / (2xy^2 ) Do numerator first: -3(x^2 y^3) (-4x y^4) = 12 x^3 y^7 So you now have: 12 x^3 y^7 / (2 x y^2) I think you can finish that off (after what Galactus told you!) Happy new year, PG :wink:
P Psychguy98 Junior Member Joined Dec 17, 2010 Messages 147 Dec 31, 2010 #3 Thanks, Denis. Happy 2011 to you!!
