8x^5/9y^2 times 3y^4/2x^3 Can I cancel the exponents x^5 and X^3?
P Psychguy98 Junior Member Joined Dec 17, 2010 Messages 147 Dec 31, 2010 #1 8x^5/9y^2 times 3y^4/2x^3 Can I cancel the exponents x^5 and X^3?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Dec 31, 2010 #2 Psychguy98 said: \(\displaystyle \frac{8x^{5}}{9y^{2}}\cdot \frac{3y^{4}}{2x^{3}}\) Can I cancel the exponents x^5 and X^3? Click to expand... When you divide exponents, just subtract the exponents. Place the result on the side that has the highest exponent. So, for example, \(\displaystyle \frac{x^{5}}{x^{3}}=x^{2}\) or \(\displaystyle \frac{x^{3}}{x^{5}}=\frac{1}{x^{2}}\) Also, don't forget to reduce the constants as well. \(\displaystyle \frac{\not{8}^{4}x^{\not{5}^{2}}}{\not{9}^{3}\not{y^{\not{2}}}}\cdot \frac{\not{3}y^{\not{4}^{2}}}{\not{2}\not{x^{\not{3}}}}\) \(\displaystyle =\frac{4x^{2}y^{2}}{3}\)
Psychguy98 said: \(\displaystyle \frac{8x^{5}}{9y^{2}}\cdot \frac{3y^{4}}{2x^{3}}\) Can I cancel the exponents x^5 and X^3? Click to expand... When you divide exponents, just subtract the exponents. Place the result on the side that has the highest exponent. So, for example, \(\displaystyle \frac{x^{5}}{x^{3}}=x^{2}\) or \(\displaystyle \frac{x^{3}}{x^{5}}=\frac{1}{x^{2}}\) Also, don't forget to reduce the constants as well. \(\displaystyle \frac{\not{8}^{4}x^{\not{5}^{2}}}{\not{9}^{3}\not{y^{\not{2}}}}\cdot \frac{\not{3}y^{\not{4}^{2}}}{\not{2}\not{x^{\not{3}}}}\) \(\displaystyle =\frac{4x^{2}y^{2}}{3}\)