Some word problems

John invested some money at 9% annual simple interest and $250 more that amount at 10% annual simple interest. If her total was $101, how much was invested at each rate?

John invested a sum of money at 10% annual simple interest and invested twice that amount at 12% annual simple interest. If his total yearly income from both investments was $2890, how much was invested at each rate?

John, a financial planner, invested a certain amount of money at 9% annual simple interest, twice that amount at 10% annual simply interest, and three times that amount at 11% annual simple interest. Find the amount invested at each rate if her total yearly income from the investments was $2790.

I need the given percentages amounts, equal to over income.

Please read the rules of participation. show your work. You MUST have SOME idea or you are in the wrong class.

Define the missing information and write a statement. Let's see what you get.

Supposed to apply a table format to get an equation. .9x+.10(250-x)=101
25-.1x=101 =7600
that's all i got.

I Need the amount of initial percentages given.

wilmot said:

Supposed to apply a table format to get an equation. .9x+.10(250-x)=101
25-.1x=101 =7600
that's all i got.

Click to expand...

Your equation should be: .09x + .10(x + 250) = 101 ; it's 250 MORE
On your answer of 7600: 7600 @ 10% = 760, 7600 @ 9% = 684 :
you should realise that's impossible, since 101 was the interest.
Looks like you're not ready to solve basic equations: suggest you talk to your teacher.

wilmot said:

Supposed to apply a table format to get an equation. .9x+.10(250-x)=101
25-.1x=101 =7600
that's all i got.

Click to expand...

You did not heed your instructions. Idare you to show me a definition in this equation. What, EXACTLY, does 'x' mean when you write it in this equation?

DEFINE it. This will help you.

One piece at a time...

"John invested some money at 9% annual simple interest"

J = Amount invested at 9% Simple

"and $250 more that amount at 10% annual simple interest"

J + $250 = Amount investted at 10% annual simple interest

"If her total was $101"

This one's a problem. What total? Pretty obviously, since the total deposit and the total accumulation must be greater than $250, I'm going to guess that this is the total interest earned over one year. Mostly, I just made that up. With an ambiguous problem statement, this is how you must proceed. Make some assumptions and work the most interesting version that comes to mind. You accomplish this by WRITING DOWN your assumptions. Having said that...

J*0.09 + (J+250.00)*0.10 = 101.00

"how much was invested at each rate?"

Excellent, we need "J" and "J+$250.00" before we think we are done.

Solving: J*0.09 + J*0.10 + 250.00*0.10 = 101.00
J*0.19 + 25.00 = 101.00
J*0.19 = 76.00
J = 400.00
J + 250 = 650

Testing: 400.00*0.09 + 650.00*0.10 = 36.00 + 65.00 = 101.00 -- Excellent. We have solved it.

Okay, now you do the next one. WRITE DOWN your definitions and assumptions. Seriously...Do NOT just throw up an equation and hope it's right. Motivate it and explain it.