mixture problem

Smith54

New member
Joined
Feb 20, 2009
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An herbalist has 30oz of hervs costing $2 per ounce. How many ounces of hervs costing $1 an ounce should be mixed with the 30iz ti oridyce a nuxtyrecistubg $1.60 per ounce.

Here's my take:

30*2 + 1x= 30*1.60
60 + 1x= 48
1x= -12
x=-12
 
Hello, Smith54!

Sorry, your equation is incorrect.


An herbalist has 30oz of herbs costing $2 per ounce.
How many ounces of herbs costing $1 an ounce should be mixed with the 30 oz to produce a mixture costing $1.60 per ounce?

\(\displaystyle \text{He has 30 oz of \$2 herbs.}\)

\(\displaystyle \text{This is worth: }\:30 \times 2 \,=\,60\text{ dollars.}\)


\(\displaystyle \text{He adds }x\text{ oz of \$1 herbs.}\)

\(\displaystyle \text{This is worth: }\:x \times 1 \,=\,x\text{ dollars.}\)


\(\displaystyle \text{The total value of the mix is: }\:60+x\text{ dollars.}\) .[1]


\(\displaystyle \text{We know that the mix will be }30 + x\text{ oz worth \$1.60 per oz.}\)

\(\displaystyle \text{The total value of the mix is: }\:1.60(30+x)\text{ dollars.}\) .[2]


\(\displaystyle \text{There is our equation! }\quad\hdots\quad 60 + x \:=\:1.60(30+x)\)

 
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